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ChemistryComplete Pblock-p-Block 17,18Medium2 minQB
ChemistryMediumsingle choice

Cold dil NaOH

Hot dil NaOH

The compound Y and Z are respectively :

Options:

Answer:
B
Solution:

Explain the Question: Products of Cl2 with NaOH under different conditions.

Concept:  Reaction of chlorine with cold and hot alkali.

Solution:

•   Cold dilute NaOH:    

Cl2 + 2NaOH → NaCl + NaOCl + H2O    

→ Y = NaOCl (bleaching powder component).

•  Hot concentrated NaOH:    

3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O    

→ Z = NaClO₃ (chlorate).

Stream:JEESubject:ChemistryTopic:Complete Pblock-Subtopic:p-Block 17,18
2mℹ️ Source: QB

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