Chemistry - Complete Pblock- Question with Solution | TestHub

Diborane ($B_2{H}_6$) reacts with ammonia ($N{H}_3$) to form an adduct $B_2{H}_6\cdot 2N{H}_3$. This adduct is an ionic compound.

The reaction proceeds as:

$B_2{H}_6+2N{H}_3\to [B{H}_2(N{H}_3{)}_2{]}^{+}[B{H}_4{]}^{-}$

This ionic formulation is known as the diammoniate of diborane.

The correct formulation is $[B{H}_2(N{H}_3{)}_2{]}^{+}[B{H}_4{]}^{-}$.