Chemistry - Complete Pblock- Question with Solution | TestHub

ChemistryComplete Pblock-p-Block 13,14Easy2 minPYQ_2022

ChemistryEasysingle choice

$Na_{2} B_{4} O_{7} ⟶ heat X + NaBO_{2}$ in the above reaction the product " $X$ " is :NEET 2022 (Phase 2)

Answer:

Solution:

$Na_{2} B_{4} O_{7} \cdot 10 H_{2} O - 10 H_{2} O ⟶ Δ Na_{2} B_{4} O_{7}$ $Na_{2} B_{4} O_{7} ⟶ Δ 2 NaBO_{2} + B_{2} O_{3} (X)$ $X =$ Boric anhydride

Stream:NEETSubject:ChemistryTopic:Complete Pblock-Subtopic:p-Block 13,14

⏱ 2mℹ️ Source: PYQ_2022

Loading discussions...