Chemistry - Complete Pblock- Question with Solution | TestHub

(i) Correct. ${\mathrm{CuSO}}_4$ reacts with excess ${\mathrm{NH}}_3$ to form the deep blue complex ion $[\mathrm{Cu}({\mathrm{NH}}_3{)}_4{]}^{2+}$.

(ii) Incorrect. ${\mathrm{PH}}_3$ is a poor ligand and does not form a stable complex with ${\mathrm{CuSO}}_4$.

(iii) Correct. Excess ${\mathrm{NH}}_3$ reacts with ${\mathrm{Cl}}_2$ to produce ${\mathrm{N}}_2$ and ${\mathrm{NH}}_4\mathrm{Cl}$.

(iv) Correct. Excess ${\mathrm{Cl}}_2$ reacts with ${\mathrm{NH}}_3$ to form ${\mathrm{NCl}}_3$ and $\mathrm{HCl}$.

(v) Correct. Concentrated ${\mathrm{H}}_2{\mathrm{SO}}_4$ dehydrates sucrose (${\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$) to carbon.

(vi) Incorrect. ${\mathrm{P}}_4{\mathrm{O}}_{10}$ is a dehydrating agent. It reacts with ${\mathrm{HNO}}_3$ to form ${\mathrm{N}}_2{\mathrm{O}}_5$ and ${\mathrm{HPO}}_3$ (metaphosphoric acid). The equation should be $4{\mathrm{HNO}}_3+{\mathrm{P}}_4{\mathrm{O}}_{10}\to 4{\mathrm{HPO}}_3+2{\mathrm{N}}_2{\mathrm{O}}_5$.

(vii) Correct. Sulfur reacts with hot concentrated ${\mathrm{H}}_2{\mathrm{SO}}_4$ to produce ${\mathrm{SO}}_2$ and ${\mathrm{H}}_2\mathrm{O}$.

(viii) Incorrect. The product should be $[{\mathrm{XeF}}_3{]}^{+}[{\mathrm{SbF}}_6{]}^{-}$.

(ix) Incorrect. Cold and dilute $\mathrm{NaOH}$ reacts with ${\mathrm{Cl}}_2$ to form $\mathrm{NaCl}$ and $\mathrm{NaClO}$ (sodium hypochlorite), not ${\mathrm{NaClO}}_3$.

Total correct reactions: 6