Chemistry - Complete Pblock- Question with Solution | TestHub

$\left(\mathrm{A}\right)$ since $\mathrm{HOCl}$ is weakest oxyacid of chlorine. Therefore $\mathrm{ClO}$ - become strongest conjugate base.

$\left(\mathrm{B}\right)$  

$\left(\mathrm{C}\right)$ $3{\mathrm{ClO}}^{-}⟶2{\mathrm{Cl}}^{-}+{\mathrm{ClO}}_3^{-} {\mathrm{K}}_{\mathrm{eq}}={10}^{27}$
In hot solution rate of disproportionation is fairly rapid.
$4{\mathrm{ClO}}_3^{-}⟶{\mathrm{Cl}}^{-}+3{\mathrm{ClO}}_4^{-} \mathrm{Keq}={10}^{29}$ It is thermodynamically possible but kinetically, it is very slow reaction.

$\left(\mathrm{D}\right)$ Lower oxyacids are good oxidizing agents.
${\mathrm{SO}}_3^{2-}+\overline{\mathrm{O}}\mathrm{Cl}⟶{\mathrm{SO}}_4^{2-}+{\mathrm{Cl}}^{-}$