Compound A reacts with NH 4 Cl and forms a compound B. Compound B reacts with H 2 O and excess of CO 2 to form compound C which on passing through or reaction with saturated NaCl solution forms sodium

Question

Compound A reacts with NH 4 Cl and forms a compound B. Compound B reacts with H 2 O and excess of CO 2 to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A. B and C, are respectively.

TestHub · Accepted Answer

When calcium hydroxide is reacted with crystals of ammonium chloride, the products formed as calcium chloride, ammonia and water.

$Ca (OH)_{2} + {NH}_{4} Cl \to {CaCl}_{2} + 2 {NH}_{3} + 2 H_{2} O$

When ammonia is reacted with water and excess carbon dioxide, it forms ammonium hydrogen carbonate which on passing through with saturated NaCl solution forms hydrogen carbonate.

${NH}_{3} + H_{2} O + {CO}_{2} \to {NH}_{4} {HCO}_{3}$

${NH}_{4} {HCO}_{3} + NaCl \to {NaHCO}_{3} ↓ + {NH}_{4} Cl$

So, the compound A, B, and C are $C a (O H)_{2}, N H_{3}, N H_{4} H C O_{3}$ respectively.

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