Given below are two statements : Statement-I : Methane and steam passed over a heated Ni catalyst produces hydrogen gas. Statement-II : Sodium nitrite reacts with NH 4 Cl to give H 2 O , N 2 and NaCl

Question

Given below are two statements :

Statement-I : Methane and steam passed over a heated $Ni$ catalyst produces hydrogen gas.

Statement-II : Sodium nitrite reacts with ${NH}_{4} Cl$ to give $H_{2} O, N_{2}$ and $NaCl$ .

In the light of the above statements, choose the most appropriate answer from the options given below :

TestHub · Accepted Answer

In steam-methane reforming, methane reacts with steam under $3 - 25 bar$ pressure in the presence of a nickel catalyst to produce hydrogen, carbon monoxide, and a relatively small amount of carbon dioxide. Steam reforming is endothermic, that is, heat must be supplied to the process for the reaction to proceed.

${NaNO}_{2} + {NH}_{4} Cl \overset{∆}{\to} N_{2} + NaCl + H_{2} O$

as ${NH}_{4} {NO}_{2} \overset{∆}{\to} N_{2} + H_{2} O$

Hence, both the statements are correct.

Chemistry - Complete P-block Question with Solution | TestHub

Options:

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