A 4 KOH, O 2 (Green) 2 B + 2 H 2 O 3 B 4 H Cl ( P u r pl e ) 2 C + M n O 2 + 2 H 2 O 2 B H 2 O , K I 2 A + 2 K OH + D In the above sequence of reactions, A

Question

A ​ ​ 4 KOH, O 2 ​ ​ (Green) 2 B ​ ​ + 2 H 2 ​ O 3 B ​ ​ 4 H Cl ​ ( P u r pl e ) 2 C ​ ​ + M n O 2 ​ + 2 H 2 ​ O 2 B ​ H 2 ​ O , K I ​ 2 A ​ ​ + 2 K OH + D ​ ​ In the above sequence of reactions, A ​ ​ and D ​ ​ respectively, are :

TestHub · Accepted Answer

A = MnO₂, as alkaline fusion of MnO₂ with KOH and O₂ forms green K₂MnO₄ (B).

B = K₂MnO₄ (Green) undergoes disproportionation with HCl to give purple KMnO₄ (C) and MnO₂.

K₂MnO₄ oxidizes I⁻ (from KI) to KIO₃ (D) while itself is reduced to MnO₂ (A).

Therefore, A = MnO₂ and D = KIO₃. Correct Answer: (C)

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