The magnetic moment of a transition metal ion is found to be 3.87 B.M. The number of unpaired electrons present in it -

Question

TestHub · Accepted Answer

For transition metal ions, the magnetic moment is given by:

$μ = n (n + 2) B . M .$

Given, $μ = 3.87$ B.M.

So, $3.87 \approx n (n + 2)$ .

Checking values: for $n = 3$ ,

$3 (3 + 2) = 15 = 3.87$ B.M.

Hence, the number of unpaired electrons = 3.

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