Chemistry - Complete d-block Question with Solution | TestHub

The reaction between ${\mathrm{MnO}}_4^{-}$ ​ with ${\mathrm{C}}_2{\mathrm{O}}_4^{2-}$ ​ is as given below:

$2{\mathrm{MnO}}_4^{-}+16{\mathrm{H}}^{+}+5{\mathrm{C}}_2{\mathrm{O}}_4^{2-} \to 2{\mathrm{Mn}}^{+2}+8{\mathrm{H}}_2\mathrm{O}+10{\mathrm{CO}}_2$

From this, we can see that $16$ moles of ${\mathrm{H}}^{+}$react with $2$ moles of ${\mathrm{MnO}}_4^{-}$​ .  Hence, one mole of permanganate requires eight moles of ${\mathrm{H}}^{+}$ ions