The metal ion (in gaseous state) with lowest spin-only magnetic moment value is

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Ion Electronic configuration No. of unpaired electron 1 Cr 2 + 3 d 4 4 2 V 2 + 3 d 3 3 3 Fe 2 + 3 d 6 4 4 Ni 2 + 3 d 8 2 Magnetic moment(spin only) is calculated by the formula μ = n ( n + 2 ) BM . Magnetic moment (spin only)is directly proportional to the number of unpaired electrons. Hence, less is the number of unpaired electrons less is the magnetic moment (spin only). As Ni 2+ has the least number of unpaired electrons it has the least magnetic moment (spin only) among the given options.

	Ion	Electronic configuration	No. of unpaired electron
1	${Cr}^{2 +}$	$3 d^{4}$	$4$
2	$V^{2 +}$	$3 d^{3}$	$3$
3	${Fe}^{2 +}$	$3 d^{6}$	$4$
4	${Ni}^{2 +}$	$3 d^{8}$	$2$

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