Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsExperimental determination of order of reactionMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

For a certain reaction, concentration of reactant (C) & time (t) are related as

$k_{1} t + ln C + k_{2} C = k_{3}$

where $k_{1}, k_{2} & k_{3}$ are constants, then what is order of reaction at

Very low concentration where $k_{2} C ≪ 1$ .

Answer:

1.00

Solution:

Given,

$k_{1} t + ln C + k_{2} C = k_{3}$

At very low concentration,

$k_{2} C ≪ 1$

so the equation becomes

$ln C = - k_{1} t + co n s t an t$

This is the integrated rate equation of a **first-order reaction**:

$ln [A] = ln [A]_{0} - k t$

$O r d ero f re a c t i o n = 1$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Experimental determination of order of reaction

⏱ 2mℹ️ Source: QB

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