The rate law for the reaction R C l + N a O H ( a q ) → R O H + N a C l is given by Rate = k [ R C l ] . The rate of the reaction will be

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ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

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The rate law for the reaction
$R C l + N a O H (a q) \to R O H + N a C l$
is given by
Rate $= k [R C l]$ . The rate of the reaction will be

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Answer:

Solution:

It is a pseudo-first-order reaction (molecularity is two but of first order) as the rate of reaction does not depend upon the concentration of aqueous NaOH as it is in excess so no effect of change of concentration of it.
Since r $\propto$ [RCl], so rate is halved when the concentration of alkyl halide is halved.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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