Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsFirst Order ReactionsMedium2 minQB

ChemistryMediumsingle choice

A radioactive sample gave 630 counts and 610 counts per min. at times differing by 1 hr . The decay constant ( $λ$ ) in $min^{- 1}$ is given by

Answer:

Solution:

Radioactive decay follows $N = N_{0} e^{- λ t}$ . Given $N_{0} / N = 630/610$ and $t = 1 h r = 60 min$ , so $e^{60 λ} = 630/610$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

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