Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawMedium2 minQB

ChemistryMediummatching list

Match column I with column II for the reaction A → products, with initial concentration of 'A' equal to 'a' M, $k =$ Rate constant

Options:

Answer:

Solution:

$t_{1/2} (zeroor d er) = \frac{a}{2 K} t_{1/2} (1^{s t} or d er) = \frac{ln 2}{K} t_{a vg} = \frac{1}{K} (1^{s t} or d er) r a d i o a c t i v e t_{1/2} (2^{n d} or d er) = \frac{1}{a K}$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: QB

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