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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawMedium2 minQB

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For the reaction $A + 2 B \to X + Y$ , rate $= - \frac{d [ A ]}{d t} = k [A]^{2} [B]$ . The expression for the rate of change in the concentration of $B, - \frac{d [ B ]}{dt}$ , would be

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Answer:

Solution:

$- \frac{d [ A ]}{d t} = k [A]^{2} [B] = - \frac{1}{2} \frac{d [ B ]}{d t}$

∴ $- \frac{d [ B ]}{d t} = 2 k [A]^{2} [B]$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: QB

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