Chemistry - Chemical Kinetics Question with Solution | TestHub

The rate of reaction is expressed as:

$Rate=-\frac{1}{2}\frac{d[A]}{dt}=-\frac{d[B]}{dt}=\frac{d[C]}{dt}$

Given $\frac{d[C]}{dt}=2.2\times 10^{-3}\mathrm{mol}{\mathrm{L}}^{-1}\mathrm{mi}{\mathrm{n}}^{-1}$.

Therefore, $-\frac{1}{2}\frac{d[A]}{dt}=2.2\times 10^{-3}$.

So, $-\frac{d[A]}{dt}=2\times 2.2\times 10^{-3}=4.4\times 10^{-3}\mathrm{mol}{\mathrm{L}}^{-1}\mathrm{mi}{\mathrm{n}}^{-1}$.