Chemistry - Chemical Kinetics Question with Solution | TestHub

$\lambda =\frac{0.693}{t_{1/2}}=\frac{0.693}{5770}=1.2\times 10^{-4}yrs$×

At the end of 5770 years, one-half of the sample would remain, ($t_{1/2}$ = 5770 years).

At the end of another 5770 years, for a total of $5770+5770=11540$ years, $\frac{1}{4}$ of the sample would remain.