Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsArrhenius EquationMedium2 minQB

ChemistryMediumnumerical

$5 mol A (t_{1/2} = 10 min)$ is introduced into a closed container where it converts into B & C by parallel first order kinetics with effective energy of activation $7.6 kcal / mol$ as :

What would be the mole fraction of B in the mixture after 20 min. from beginning.

Answer:

0.30

Solution:

$E_{a} = \frac{k _{1} E _{1} + k _{2} E _{2}}{k _{1} + k _{2}}$

$\frac{k _{1}}{k _{2}} = \frac{2}{3}$

$n_{B} = 3.75 \times \frac{2}{5}$

$x_{B} = \frac{3.75 \times \frac{2}{5}}{5} = 0.30$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Arrhenius Equation

⏱ 2mℹ️ Source: QB

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