Home
PYQ PracticeFree
JEE Rank Predictor
Answer Key

Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsFirst Order ReactionsMedium2 minQB

ChemistryMediuminteger

Passage / Comprehension

A definite volume of H₂O₂ undergoing decomposition required 25.6 mL of standard KMnO₄ solution for titration. After 10 and 20 minutes, the volumes of permanganate required were 16 mL and 10 mL, respectively. [log₂ = 0.3; $(1.6)^{5} = (3.2)^{2}$ ]

The time (in min.) required for the decomposition to be half complete is.

Answer:

Solution:

For $H_{2} O_{2}$ titrated with $KMnO_{4}$

$K = \frac{2.303}{10} lo g \frac{25.6}{16}$

$\frac{2.303 \times 0.3}{t _{1/2}} = \frac{2.303}{10} lo g 1.6$

$t_{1/2} = \frac{3}{0.2} = 15 min$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...