When concentration of reactant in a reaction A → B is increased 8 times, the rate increases only 2 times. The order of reaction would be

r = k [ A ] n . 2 r = k [ 8 A ] n = k [ 2 3 A ] n . ∴ n = 3 1 .

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ChemistryChemical KineticsExperimental determination of order of reactionMedium2 minQB

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When concentration of reactant in a reaction $A \to B$ is increased 8 times, the rate increases only 2 times. The order of reaction would be

Answer:

Solution:

$r = k [A]^{n}$ .

$2 r = k [8 A]^{n} = k [2^{3} A]^{n}$ .

∴ $n = \frac{1}{3}$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Experimental determination of order of reaction

⏱ 2mℹ️ Source: QB

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