Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsFirst Order ReactionsMedium2 minQB

ChemistryMediummultiple choice

For a first order reaction

Answer:

A, D

Solution:

A $⟶$ B

$t = 0$ : $a$ $0$

$t = t$ : $(a - x)$ $x$

$t = \frac{2.303}{k} lo g \frac{a}{a - x}$

or $k t = ln \frac{a}{a - x}$

$e^{k t} = \frac{a}{a - x}$

$e^{- k t} = \frac{a - x}{a} = 1 - \frac{x}{a}$

So, $\frac{x}{a} = (1 - e^{- k t})$

$ln k = A e^{- \frac{E _{a}}{RT}}$

units of $k$ and $A$ are the same and the unit of each is $T^{- 1}$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

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