Chemistry - Chemical Kinetics Question with Solution | TestHub

From question

$\frac{2{\text{k}}_1}{2{\text{k}}_1+3{\text{k}}_2}=\text{0.5}and{k}_1+{\text{k}}_2=\frac{\text{0.693}}{\text{1.386}\times 10^2}=5\times 10^{-3}{h}^{-1}$

Solving$\frac{{\text{k}}_1}{{\text{k}}_2}=\frac{3}{2}and{\text{k}}_1=3\times 10^{-3}{h}^{-1}and k_2=2\times 10^{-3}{h}^{-1}$

${\text{t}}_{1/2\left(\text{A}\to \text{B}\right)}=\frac{\text{0.693}}{{\text{k}}_1}=\frac{\text{0.693}}{3\times 10^{-3}}=231h$