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ChemistryChemical KineticsRate of Reactions/Rate LawMedium2 minQB

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For a reaction : $A + B + C \to P$

Rate law is given by

$R = K [A]^{1} [B]^{2} [C]^{0}$

If concentration of A is doubled, B is tripled and C is halved. Calculate ratio of new rate of reaction to that of the initial rate of reaction :

Answer:

Solution:

$R = K [A] [B]^{2} [C]^{0}$

$R^{'} = K [2 A] [3 B]^{2} [C]^{0}$

$\frac{R ^{'}}{R} = 2 \times 3^{2} = 18$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: QB

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