On 75% hydrolysis completion, which relationship holds true - | TestHub

Passage / Comprehension

Hydrolysis of ester follows first-order kinetics in the presence of an acid catalyst.

$RCOOR^{'} + H_{2} O \to RCOOH + R^{'} OH$

To study its kinetics, a fixed amount of reaction mixture is taken and titrated with a strong base like NaOH, which reacts with the acid formed and the catalyst present. By measuring the volume of NaOH required at different intervals of time, the following observations are made for one such reaction's progress.

On $75%$ hydrolysis completion, which relationship holds true -

Options:

Answer:

Solution:

$V_{0} =$ Volume of NaOH used at $t = 0$

$V_{t} =$ Volume of NaOH used at $t^{'}$

$V_{\infty} =$ Volume of NaOH used at $t = \infty$

a $\propto (v_{\infty} - v_{0})$

$(a - x) \propto (v_{\infty} - v_{t}) RCOOR^{'} + H_{2} O \to RCOOH + R^{'} OH$ $\frac{a}{( a - x )} = \frac{( v _{\infty} - v _{0} )}{( v _{\infty} - t _{t} )} x = \frac{3}{4}$

$\frac{1}{1 - \frac{3}{4}} = \frac{V _{\infty} - V _{0}}{V _{\infty} - V _{t}} \Rightarrow 4 = \frac{V _{\infty} - V _{0}}{V _{\infty} - V _{t}}$

$4 v_{\infty} - 4 v_{t} = v_{\infty} - v_{0}$

$(3 v_{\infty} + v_{0}) = 4 v_{t}$

Chemistry - Chemical Kinetics Question with Solution | TestHub

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Doubts & Discussion