The vapour pressure of two miscible liquids (A) and (B) are 300 and 500 mm of Hg respectively. In a flask 10 mole of (A) is mixed with 12 mole of (B). However, as soon as (B) is added. (A) starts poly

Question

The vapour pressure of two miscible liquids (A) and (B) are 300 and 500 mm of Hg respectively. In a flask 10 mole of (A) is mixed with 12 mole of (B). However, as soon as (B) is added. (A) starts polymerizing into a completely insoluble solid. The polymerization follows first - order kinetics. After 100 minute, 0.525 mole of a solute is dissolved which arrests the polymerization completely. The final vapour pressure of the solution is 400 mm of Hg .

Assume negligible volume change on mixing and polymerization and ideal behavior for the final solution, the rate constant of the polymerization of A is:

TestHub · Accepted Answer

t t 400 400 4 ( a + 12.525 ) 4 a + 50.100 a K A ​ ( 100 ) K A ​ ​ = 0 10 n A ⟶ A n ​ = ( 10 − n x = a ) x = P A o ​ x A ​ + P B o ​ x B ​ = a + 12.525 300 a ​ + a + 12.525 500 × 12 ​ = 3 a + 60 = 3 a + 60 = 9.9 = ln ( 9.9 10 ​ ) = 100 0.01 ​ = 1 0 − 4 mi n − 1 ​

Chemistry - Chemical Kinetics Question with Solution | TestHub

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JEE Advanced 2027 (Class 12)