Chemistry - Chemical Kinetics Question with Solution | TestHub

The rate of reaction is given by the expression:

$\text{Rate}=-\frac{1}{2}\frac{\Delta [{\text{N}}_2{\text{O}}_5]}{\Delta t}$

$\Delta [{\text{N}}_2{\text{O}}_5]=1.36\times 10^{-2}-1.63\times 10^{-2}=-0.27\times 10^{-2}{\text{mol L}}^{-1}$

$\Delta t=400\text{s}$

$\text{Rate}=-\frac{1}{2}\left(\frac{-0.27\times 10^{-2}}{400}\right)$

$\text{Rate}=\frac{0.27\times 10^{-2}}{800}=3.375\times 10^{-6}{\text{mol L}}^{-1}{\text{s}}^{-1}$

Rounding off, the rate of reaction is $3.38\times 10^{-6}{\text{mol L}}^{-1}{\text{s}}^{-1}$.

Answer: $3.38\times 10^{-6}{\text{mol L}}^{-1}{\text{s}}^{-1}$