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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsMedium2 minPYQ_2025

ChemistryMediumsingle choice

If the rate constant of a reaction is $0.03 s^{- 1}$ , how much time does it take for $7.2 mol L^{- 1}$ concentration of the reactant to get reduced to $0.9 mol L^{- 1}$ ? (Given $: lo g 2 = 0.301$ )NEET 2025

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Answer:

Solution:

$K = 0.03 s^{- 1} (First order reaction) A_{0} = 7.2 mol L^{- 1} A_{t} = 0.9 mol L^{- 1} 7.2 t_{1/2} 3.6 t_{1/2} 1.8 t_{1/2} 0.9 t = 3 t_{1/2} = \frac{3 \times 0.693}{0.03} = 69.3 s$

Stream:NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2025

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