Consider the following plots of log of rate constant $k (lo g k)$ vs $\frac{1}{T}$ for three different reactions. The correct order of activation energies of these reactions is

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Consider the following plots of log of rate constant k ( lo g k ) vs T 1 ​ for three different reactions. The correct order of activation energies of these reactions is

TestHub · Accepted Answer

​ K = A e − E a RT logk = lo g A − 2.303 RT Ea ​ ​ For graph between logk with T 1 ​ ∣ Slope of curve ​ = 2.303 R Ea ​ From given graph Magnitude of slope ⇒ ( 2 ) > ( 1 ) > ( 3 ) Hence Ea 2 ​ > Ea 1 ​ > Ea 3 ​

Chemistry - Chemical Kinetics Question with Solution | TestHub

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