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ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

$16 g$ of a radio active substance is reduced to $0 .5 g$ after $1$ hour. The half life of the radioactive substance in minutes is

Answer:

12.00

Solution:

$λ = \frac{1}{t} l n \frac{16}{0.5}$
$λ = 5 \times l n 2$
$t_{\frac{1}{2}} = \frac{l n 2}{λ} = \frac{1}{5} h r = 12 m i n$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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