Chemistry - Chemical Kinetics Question with Solution | TestHub

The Arrhenius equation is given by $k=A{e}^{-E_a/RT}$

Taking the logarithm to the base $10$ on both sides, we get:

${\log }_{10}k={\log }_{10}A-\frac{E_a}{2.303RT}$

This equation is of the form $y=mx+c$, which represents a straight line.

Here, $y={\log }_{10}k$ and $x=\frac{1}{T}$

The slope of the line is $m=-\frac{E_a}{2.303R}$

The y-intercept is $c={\log }_{10}A$

Thus, in the plot of ${\log }_{10}k$ versus $\frac{1}{T}$, the intercept on the y-axis is ${\log }_{10}A$.

Answer: ${\log }_{10}\mathrm{A}$