Start Free Mock LoginAlready registered? Login here

Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsEasy2 minPYQ_2020

ChemistryEasysingle choice

A first order reaction is $25%$ completed in 40 minutes. What is the rate constant $k$ for the reaction?

Options:

Answer:

Solution:

(B) $[A]_{0} k ∴ k = 100, [A]_{t} = 100 - 25 = 75, t = 40 min = \frac{2.303}{t} lo g_{10} \frac{[ A ] _{0}}{[ A ] _{t}} = \frac{2.303}{40} lo g_{10} \frac{100}{75} = \frac{2.303 \times lo g 1.33}{40}$

Stream:MHT_CETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...