Chemistry - Chemical Kinetics Question with Solution | TestHub

Given:
Initial concentration, $[A{]}_0=0.08{\text{ mol dm}}^{-3}$
Ratio of initial concentration to concentration at time $t$, $\frac{[A{]}_0}{[A{]}_t}=5.00$

We need to find the concentration remaining after 40 minutes, which is $[A{]}_t$.

Using the given ratio:
$[A{]}_t=\frac{[A{]}_0}{5.00}$

Substituting the value of $[A{]}_0$:
$[A{]}_t=\frac{0.08}{5.00}=0.016{\text{ mol dm}}^{-3}$

Answer: $0.016\mathrm{mol}{\mathrm{dm}}^{-3}$