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ChemistryChemical KineticsArrhenius EquationMedium2 minPYQ_2010

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A chemical reaction wascarried out at $320 K$ and $300 K$ . The rate constants were found to be $k_{1}$ and $k_{2}$ respectively. Then

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Solution:

As we know that for every $1 0^{\circ}$ rise in temperature, rate constant, $k$ becomes doubled. Hence, on rising the temperature $2 0^{\circ}$ , the rate constant will be four times, i.e., $k_{1} = 4 k_{2} \Rightarrow k_{2} = \frac{1}{4} k_{1} = 0.25 k_{1}$

Stream:VITEEESubject:ChemistryTopic:Chemical KineticsSubtopic:Arrhenius Equation

⏱ 2mℹ️ Source: PYQ_2010

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