The rate constants for decomposition of acetaldehyde have been measured over the temperature range $700 - 1000 K$ . The data has been analysed by plotting $lnk$ vs $\frac{10^{3}}{T}$ graph. The value of activation energy for the reaction is ${kJmol}^{- 1}$ . (Nearest integer) (Given : $R = 8.31 J K^{- 1} {mol}^{- 1}$ )

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k = Ae - E a RT lnk = lnA - E a RT lnk = lnA + - E a 1000 R 1000 T Slope = - E a 1000 R = - 18 . 5 E a = 18 . 5 × 1000 × 8 . 31 = 153 . 735 × 10 3 J = 154 KJ

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