Chemistry - Chemical Kinetics Question with Solution | TestHub

To calculate value of $E_a$ Equation used is $\log \left(\frac{k_2}{k_1}\right)=\frac{E_a}{2.303R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right)$ Hence $E_a$ can be calculated if value of rate constant $k$ is known at two different temperatures $T_1$ and ${\mathrm{T}}_2$.