For a first order reaction, the time required for completion of $90 %$ reaction is ' $x$ ' times the half life of the reaction. The value of ' $x$ ' is
(Given: $\ln 10 = 2.303$ and $\log 2 = 0.3010$ )

Question

For a first order reaction, the time required for completion of 90 % reaction is ' x ' times the half life of the reaction. The value of ' x ' is (Given: ln 10 = 2 . 303 and log 2 = 0 . 3010 )

TestHub · Accepted Answer

ln 2 t 1 / 2 t 90 % = ln 100 10 = ln 10 t 90 % × 0 .693 t 1 / 2 = 2 .303 t 90 % = 2 . 303 0693 × t 1 / 2 = 3 .32 t 1 / 2 Hence, x = 3 . 32

Chemistry - Chemical Kinetics Question with Solution | TestHub

Options:

Doubts & Discussion