For the first order reaction, t 99% = x × t 90% . The value of x will be

t 99 = k 1 ln 100 ; t 90 = k 1 ln 10 100 t 90 t 99 = l n 10 l n 100 = 1 2 = 2 Hence, x = 2 .

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ChemistryChemical KineticsFirst Order ReactionsMedium2 minQB

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For the first order reaction, $t_{99%} = x \times t_{90%}$ .

The value of x will be

Answer:

Solution:

$t_{99} = \frac{1}{k} ln 100; t_{90} = \frac{1}{k} ln \frac{100}{10}$

$\frac{t _{99}}{t _{90}} = \frac{l n 100}{l n 10} = \frac{2}{1} = 2$

Hence, $x = 2$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

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