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ChemistryChemical KineticsZero Order ReactionsMedium2 minPYQ_2021

ChemistryMediumnumerical

For a first order reaction, the ratio of the time for $75 %$ completion of a reaction to the time for $50 %$ completion is ___________ . (Integer answer)

Answer:

2.00

Solution:

$T = \frac{2.303}{k} \log (\frac{100}{100 - x %})$
$T_{75 %} = \frac{2.303}{k} \log (\frac{100}{25})$
$T_{50 %} = \frac{2.303}{k} \log (\frac{100}{50})$
$\frac{T_{75 %}}{T_{50 %}} = \frac{\log 4}{\log 2} = 2$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Zero Order Reactions

⏱ 2mℹ️ Source: PYQ_2021

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