Start Free Mock LoginAlready registered? Login here

Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsEasy2 minPYQ_2021

ChemistryEasysingle choice

Which is rate constant of a first order reaction if 0.08 mole of reactant reduces to 0.02 mole in 23.03 minute?

Options:

Answer:

Solution:

$K = \frac{2.303}{t} lo g \frac{[ A ] _{0}}{[ A ] _{t}} K = \frac{2.303}{23.03} \cdot lo g \frac{0.08}{0.02} K = \frac{1}{10} lo g 4 = \frac{2 lo g 2}{10} = 0.0602 min^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...