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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsHard2 minPYQ_2020

ChemistryHardsingle choice

The half-life for a zero order reaction having $0.02 M$ initial concentration of reactant is $100 s$ . The rate constant (in $mol L^{- 1} s^{- 1}$ ) for the reaction isNEET 2020 (Phase 2)

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Answer:

Solution:

${(t_{1 / 2})}_{zero} = \frac{[A]_{0}}{2 K}$

$100 s = \frac{0.02 M}{2 K}$
$K = \frac{0.02 M}{2 \times 100} = 1 \times 10^{- 4} mol L^{- 1} s^{- 1}$

Stream:NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2020

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