Chemistry - Chemical Kinetics Question with Solution | TestHub

For, 2NO + O₂ ⟶ 2NO₂

Rate = $K[NO{]}^2[O_2]$

Let $a$ mole of NO and $b$ mole of O₂ be taken to start a reaction at any time in a vessel of $V$ litre.

∴$r_1=K{\left[\frac{a}{V}\right]}^2\left[\frac{b}{V}\right].\dots \dots (1)$

If the volume of the vessel is reduced to $V/4$, then for the same moles of NO and O₂,

$r_2=K{\left[\frac{a}{V/4}\right]}^2\left[\frac{b}{V/4}\right]=64K{\left[\frac{a}{V}\right]}^2\left[\frac{b}{V}\right]..\dots (2)$

By Equations (1) and (2),

$\frac{r_2}{r_1}=64$

or $r_2$ is 64 times of$r_1$.