For the decomposition of H I at 1000 K 2 H I → H 2 + I 2 , the following data were obtained Conc. Of HI(M) Rate of decomposition of HI (mole/unit sec) 0.1 2.75 × 10 − 8 0.2 11 × 10 − 8 0.3 24.75 × 10 − 8 The order of reaction is :

R a t e = k H I n 11 × 10 - 8 = k 0.2 n . . . i 2.75 × 10 - 8 = k 0.1 n . . . i i Dividing eq. (i) by eq. (ii), 4 = 2 n , n = 2

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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsOrder and Molecularity of ReactionsEasy2 minPYQ_2020

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For the decomposition of $H I$ at $1000 K (2 H I \to H_{2} + I_{2})$ , the following data were obtained

Conc. Of HI(M)	Rate of decomposition of HI (mole/unit sec)
$0.1$	$2.75 \times 10^{- 8}$
$0.2$	$11 \times 10^{- 8}$
$0.3$	$24.75 \times 10^{- 8}$

The order of reaction is :

Options:

Answer:

Solution:

$R a t e = k {[H I]}^{n}$

$11 \times 10^{- 8} = k {[0.2]}^{n} . . . (i)$

$2.75 \times 10^{- 8} = k {[0.1]}^{n} . . . (i i)$

Dividing eq. (i) by eq. (ii),

$4 = 2^{n}, n = 2$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Order and Molecularity of Reactions

⏱ 2mℹ️ Source: PYQ_2020

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