Chemistry - Chemical Kinetics Question with Solution | TestHub

$4{\mathrm{NH}}_3+5{\mathrm{O}}_2\to 4\mathrm{NO}+6{\mathrm{H}}_2\mathrm{O}$ Rate of reaction $=-\frac{1}{4}\frac{\mathrm{d}\left[{\mathrm{NH}}_3\right]}{\mathrm{dt}}=-\frac{1}{5}\frac{\mathrm{d}\left[{\mathrm{O}}_2\right]}{\mathrm{dt}}=\frac{1\mathrm{d}[\mathrm{NO}]}{4}=\frac{1}{6}\frac{\mathrm{d}\left[{\mathrm{H}}_2\mathrm{O}\right]}{\mathrm{dt}}$ $\therefore$ Rate of formation of water, $\frac{\mathrm{d}\left[{\mathrm{H}}_2\mathrm{O}\right]}{\mathrm{dt}}=\frac{6}{4}\frac{\mathrm{d}\left[{\mathrm{NH}}_3\right]}{\mathrm{dt}}$ $$=\frac{6}{4}\times 3.6\times 10^{-3}=5.4\times 10^{-3}\mathrm{M}/\mathrm{s}$$