Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2024

ChemistryEasysingle choice

In the chemical reaction $A \to B$ , what is the order of the reaction? Given that, the rate of reaction doubles if the concentration of $A$ is increased four times.

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Answer:

Solution:

We know, $r_{1} = k [A]^{n}$ ....(i) If conc. of $A$ is increased four times rate of reaction on doubles. $2 r_{1} = k [4 A]^{n}$ ....(ii) Divide Eq. (ii) by (i). $\frac{2 r _{i}}{r _{1}} = \frac{k ( 4 A ) ^{n}}{k ( A ) ^{n}}$ $\Rightarrow 2 = (4)^{n} \Rightarrow 2 n = (2)^{2 n} \Rightarrow n = 0.5$

Stream:BITSATSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2024

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