The reaction N 2 O 5 ⟶ 2 NO 2 + 2 1 O 2 is first order in N 2 O 5 having rate constant 6 ⋅ 2 × 1 0 − 4 s − 1 . What is the value of rate of reaction when concentration of N 2 O 5 is 1 ⋅ 25 mol L − 1 ?

N 2 O 5 ⟶ 2 NO 2 + 2 1 O 2 For first order reaction, Rate = k [ N 2 O 5 ] = 6.2 × 1 0 − 4 s − 1 × 1.25 mol L

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ChemistryChemical KineticsSecond & nth Order ReactionsMedium2 minPYQ_2020

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The reaction $N_{2} O_{5} ⟶ 2 NO_{2} + \frac{1}{2} O_{2}$ is first order in $N_{2} O_{5}$ having rate constant $6 \cdot 2 \times 1 0^{- 4} s^{- 1} .$ What is the value of rate of reaction when concentration of $N_{2} O_{5}$ is $1 \cdot 25 mol L^{- 1}$ ?

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Solution:

$N_{2} O_{5} ⟶ 2 NO_{2} + \frac{1}{2} O_{2}$ For first order reaction, $Rate = k [N_{2} O_{5}] = 6.2 \times 1 0^{- 4} s^{- 1} \times 1.25 mol L$

Stream:MHT_CETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2020

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