Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawMedium2 minQB

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Passage / Comprehension

Initially only A(g) is introduced in a closed and rigid container at constant temperature and it reacts according to first order kinetics as :

2A(g) —→ 2B(g) + C(g)

Total pressure of gas mixture in container at different times is recorded as :

What will be approximate value of rate constant for disappearance of A ? ( $ℓ n 5 = 1.6, ℓ n 2 = 0.7$ )

Answer:

Solution:

$2 A (g) \to 2 B (g) + C (g)$

At $t = 0$ : $P_{0}$ – –

At $t = 10 min$ : $P_{0} - P$ $P$ $\frac{P}{2}$

At $t = \infty$ : – $P_{0}$ $\frac{P _{0}}{2}$

$P_{t} = P_{0} + \frac{P}{2}$ $\frac{3 P _{0}}{2} = P_{\infty}$

$P = 0.6 a t m$ $P = 1 a t m$

$K = \frac{1}{t} ln (\frac{P _{0}}{P _{0} - P})$

$K = \frac{1}{10} (\frac{1}{1 - 0.6})$

$K = 9 \times 1 0^{- 2} mi n^{- 1}$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: QB

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