Chemistry - Chemical Kinetics Question with Solution | TestHub

Binding energy of electron$=\mathrm{h}{\mathrm{\nu }}_0$
$=6.6\times 10^{-34}\mathrm{k}\mathrm{g}{\mathrm{m}}^2{\mathrm{s}}^{-1}\times 2.5\times 10^{14}{\mathrm{s}}^{-1}$
$=16.5\times 10^{-20}$J
Binding energy of 1 mol${\mathrm{e}}^{-}=16.5\times 10^{-20}\frac{\mathrm{J}}{{\mathrm{e}}^{-1}}\times \frac{6.023\times 10^{23}}{1\mathrm{m}\mathrm{o}\mathrm{l}}{\mathrm{e}}^{-}$
$=99.38\times 10^3$J/mol
$=99.38$kJ/mol