Chemistry - Chemical Kinetics Question with Solution | TestHub

The variation of 'k' with 'T' is given by
${\text{k}}_{\text{T}}\text{=}{\text{k}}_{\text{0}}{\left(\text{μ}\right)}^{\frac{\text{t}}{\text{10}}}$
where μ is temperature coefficient
$\therefore \text{ln}{\text{k}}_{\text{T}}\text{=}\text{ln}{\text{k}}_{\text{0}}\text{+}\frac{\text{t}}{\text{10}}\text{ln}\text{μ}$
comparing with given eqⁿwe get$\text{μ}\text{=}\text{3}$