Chemistry - Chemical Kinetics Question with Solution | TestHub

$\mathrm{k}=4.606\times {10}^{-3}{\mathrm{s}}^{-1}$

$\mathrm{k}=\frac{2.303}{\mathrm{t}}\log \frac{{\mathrm{C}}_{\circ }}{{\mathrm{C}}_{\mathrm{t}}}$

where ${\mathrm{C}}_{\circ }$= initial concentration

${\mathrm{C}}_{\mathrm{t}}$= concentration after time t

$\mathrm{k}=\frac{2.303}{\mathrm{t}}{\log }_{10}\frac{2}{0.2}$

$4.606\times {10}^{-3}\times \mathrm{t}=2.303\times \log 10$

$\mathrm{t}=\frac{1000}{2}=500 \mathrm{s}$